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中级

实现取消规则动态配置验证

未完成
中级参考 代码结构已给出，请填写 ____ 处 
def solve():
    def validate_rule(____):
        errs=[]
        if r['____'] not in ['____','____','____']: errs.append(____)
        if not(-____<=int(r.get(____))<=____): errs.append(____)
        if not(____<=int(r.get(____))<=____): errs.append(____)
        if not(____<=int(r.get(____))<=____): errs.append(____)
        if float(r.get(____))<____: errs.append(____)
        return len(____)==____, errs
    tests=[
        {'____':'____','____':____,'____':____,'____':____,'____':____},
        {'____':'____','____':-____,'____':____,'____':____,'____':____},
        {'____':'____','____':____,'____':____,'____':____,'____':-____},
        {'____':'____','____':____,'____':____,'____':____,'____':____},
    ]
    print(____)
    for r in tests:
        ok,errs=validate_rule(____)
        print(____)

示例

输入
solve()
期望输出
Cancel rule validation:
  lunch H=9: VALID []
  breakfast H=22: VALID []
  dinner H=25: INVALID ['invalid_hour', 'negative_fee']
  supper H=20: INVALID ['invalid_meal_type']
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