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中级

实现CPD活动日费用计算

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中级参考 代码结构已给出，请填写 ____ 处 
def solve():
    from pyodide.http import open_url
    from io import StringIO
    import pandas as pd
    ds_csv = open_url(____).read()
    sch_csv = open_url(____).read()
    bc_csv = open_url(____).read()
    bld_csv = open_url(____).read()
    scr_csv = open_url(____).read()
    daily_stats = pd.read_csv(StringIO(____))
    schedules = pd.read_csv(StringIO(____))
    configs = pd.read_csv(StringIO(____))
    buildings = pd.read_csv(StringIO(____))
    screens = pd.read_csv(StringIO(____))
    cpd_stats = daily_stats[daily_stats['____']=='____']
    CPD_PRICE = float(____)
    def count_active_buildings(____):
        cmp_sch = schedules_df[(____)&(____)]
        scr_ids = set(____)
        scr_blds = screens_df[screens_df['____'].isin(____)]
        return len(scr_blds['____'].unique())
    print("____"+str(____)+"____")
    for _, row in cpd_stats.head(____).iterrows():
        bld_count = count_active_buildings(____)
        cost = round(____)
        print("____"+row['____']+"____"+row['____']+"____"+str(____)+"____"+str(____)+"____"+str(____))
    print("____"+str(len(____)))

示例

输入
solve()
期望输出
CPD daily cost calculation (CPD price=80.0 CNY/building/day):
  CMP-0007 2026-06-01 buildings=4 cost=320.0 recorded=400.0
  CMP-0007 2026-06-02 buildings=4 cost=320.0 recorded=480.0
  CMP-0007 2026-06-03 buildings=4 cost=320.0 recorded=240.0
  CMP-0007 2026-06-04 buildings=4 cost=320.0 recorded=400.0
  CMP-0007 2026-06-05 buildings=4 cost=320.0 recorded=720.0
  CMP-0007 2026-06-06 buildings=4 cost=320.0 recorded=720.0
  CMP-0007 2026-06-07 buildings=4 cost=320.0 recorded=160.0
  CMP-0016 2026-06-01 buildings=3 cost=240.0 recorded=320.0
Total CPD rows: 35
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