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中级

实现指令超时重发机制

未完成
中级参考 代码结构已给出，请填写 ____ 处 
def solve():
    from pyodide.http import open_url
    from io import StringIO
    import pandas as pd
    cmd_csv = open_url(____).read()
    cmds = pd.read_csv(StringIO(____))
    MAX_RETRY = ____
    TIMEOUT = ____
    now = ____
    def check_retry(____):
        if row['____'] in (____): return '____', ____
        if row['____'] >= MAX_RETRY: return '____', row['____']
        elapsed = now - row['____']
        if elapsed > TIMEOUT: return '____', row['____'] + ____
        return '____', row['____']
    print("____" + str(____) + "____")
    for _, row in cmds.iterrows():
        action, count = check_retry(____)
        print("____" + row['____'] + "____" + row['____'] + "____" + str(____) + "____" + action)

示例

输入
solve()
期望输出
Retry check (now=1748736700.0):
  CMD001 (acked retry=0): -> no_action
  CMD002 (acked retry=1): -> no_action
  CMD003 (failed retry=3): -> no_action
  CMD004 (sent retry=0): -> retry
  CMD005 (acked retry=0): -> no_action
  CMD006 (pending retry=0): -> retry
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