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初级

将grade和subGrade转为有序整数

未完成
初级参考 完整示例代码供参考，建议自己理解后重新输入 
def solve():
    from pyodide.http import open_url
    from io import StringIO
    loans_raw_csv = open_url("https://data.zuihe.com/dbd/riskctrl/state_02/loans_raw.csv").read()
    loans_clean_csv = open_url("https://data.zuihe.com/dbd/riskctrl/state_02/loans_clean.csv").read()
    import pandas as pd
    from io import StringIO
    df = pd.read_csv(StringIO(loans_raw_csv))
    grade_map={g:i+1 for i,g in enumerate('ABCDEFG')}
    df['grade_num'] = df['grade'].map(grade_map)
    def sg(v):
        v=str(v)
        if len(v)<2: return None
        return (ord(v[0])-ord('A'))*5+int(v[1]) if v[1].isdigit() else None
    df['subgrade_num'] = df['subGrade'].apply(sg)
    print("grade_num:"); print(df['grade_num'].describe().round(2).to_string())
    print("subgrade_num:"); print(df['subgrade_num'].describe().round(2).to_string())

示例

输入
solve()
期望输出
grade_num:
count    10000.00
mean         2.74
std          1.29
min          1.00
25%          2.00
50%          3.00
75%          4.00
max          7.00
subgrade_num:
count    10000.00
mean        11.69
std          6.39
min          1.00
25%          7.00
50%         11.00
75%         16.00
max         35.00
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