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初级

统计各支行的开户客户数

未完成
初级参考 完整示例代码供参考，建议自己理解后重新输入 
def solve():
    from pyodide.http import open_url
    offices_csv = open_url("https://data.zuihe.com/dbd/core/state_01/offices.csv").read()
    staff_csv = open_url("https://data.zuihe.com/dbd/core/state_01/staff.csv").read()
    currencies_csv = open_url("https://data.zuihe.com/dbd/core/state_01/currencies.csv").read()
    savings_products_csv = open_url("https://data.zuihe.com/dbd/core/state_01/savings_products.csv").read()
    interest_rate_charts_csv = open_url("https://data.zuihe.com/dbd/core/state_01/interest_rate_charts.csv").read()
    clients_csv = open_url("https://data.zuihe.com/dbd/core/state_01/clients.csv").read()
    savings_accounts_csv = open_url("https://data.zuihe.com/dbd/core/state_01/savings_accounts.csv").read()
    import sqlite3
    import pandas as pd
    from io import StringIO

    conn = sqlite3.connect(':memory:')
    pd.read_csv(StringIO(offices_csv)).to_sql('offices', conn, index=False, if_exists='replace')
    pd.read_csv(StringIO(clients_csv)).to_sql('clients', conn, index=False, if_exists='replace')

    result = pd.read_sql_query("""
        SELECT o.name AS office_name, COUNT(c.id) AS client_count
        FROM offices o
        LEFT JOIN clients c ON c.office_id = o.id
        WHERE o.level IN ('SUB_BRANCH','HEADQUARTERS','BRANCH')
        GROUP BY o.id, o.name
        HAVING client_count > 0
        ORDER BY client_count DESC
    """, conn)
    print(result.to_string(index=False))
    conn.close()

示例

输入
solve()
期望输出
office_name  client_count
     上海浦东支行             6
     北京朝阳支行             5
     广州天河支行             5
     北京海淀支行             4
   阳光商业银行总行             2
   阳光银行北京分行             1
   阳光银行上海分行             1
   阳光银行广州分行             1
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