← 返回题库
初级

查询订单明细及商品信息

未完成 100%
初级参考 完整示例代码供参考,建议自己理解后重新输入
def solve():
    from pyodide.http import open_url
    users_csv = open_url("https://data.zuihe.com/dbd/ecommerce/state_A01/users.csv").read()
    categories_csv = open_url("https://data.zuihe.com/dbd/ecommerce/state_A01/categories.csv").read()
    products_csv = open_url("https://data.zuihe.com/dbd/ecommerce/state_A01/products.csv").read()
    orders_csv = open_url("https://data.zuihe.com/dbd/ecommerce/state_A01/orders.csv").read()
    order_items_csv = open_url("https://data.zuihe.com/dbd/ecommerce/state_A01/order_items.csv").read()
    import sqlite3
    import pandas as pd
    from io import StringIO

    conn = sqlite3.connect(':memory:')
    pd.read_csv(StringIO(orders_csv)).to_sql('orders', conn, index=False, if_exists='replace')
    pd.read_csv(StringIO(order_items_csv)).to_sql('order_items', conn, index=False, if_exists='replace')
    pd.read_csv(StringIO(products_csv)).to_sql('products', conn, index=False, if_exists='replace')

    result = pd.read_sql_query("""
        SELECT p.name, oi.qty, oi.price, oi.qty * oi.price AS subtotal
        FROM order_items oi
        JOIN products p ON oi.product_id = p.id
        WHERE oi.order_id = 2
        ORDER BY subtotal DESC
    """, conn)
    print(result.to_string(index=False))
    conn.close()

示例

输入
solve()
期望输出
name  qty  price  subtotal
苹果iPhone15 Pro 黑色256G    1 8999.0    8999.0
  OPPO Find X7 黑色256G    1 4499.0    4499.0
         索尼WH-1000XM5    1 2499.0    2499.0
       苹果AirPods Pro2    1 1899.0    1899.0
      华为FreeBuds Pro3    1 1099.0    1099.0
Python 代码 🔒 登录后使用
🔒

登录后即可练习

注册免费账号,在浏览器中直接运行 Python 代码