角度转弧度并计算正切值

def solve():
    import matplotlib.pyplot as plt
    import numpy as np
    from math import tan, radians, pi
    
    angle_deg = 116.57
    angle_rad = angle_deg * pi / 180
    tan_value = tan(angle_rad)
    
    angles = np.linspace(0, 2*pi, 100)
    tan_values = [np.tan(a) for a in angles]
    
    plt.figure(figsize=(10, 6))
    angles_plot = np.linspace(-pi, pi, 1000)
    plt.plot(angles_plot, np.tan(angles_plot), 'b-', label='tan(θ)')
    plt.axvline(x=angle_rad, color='r', linestyle='--', label=f'θ = {angle_deg}° = {angle_rad:.4f} rad')
    plt.axhline(y=tan_value, color='g', linestyle=':', label=f'tan(θ) ≈ {tan_value:.2f}')
    
    plt.ylim(-5, 5)
    plt.axhline(y=0, color='k', linewidth=0.5)
    plt.axvline(x=0, color='k', linewidth=0.5)
    plt.grid(alpha=0.3)
    plt.legend()
    plt.title('角度与正切值')
    plt.xlabel('θ (弧度)')
    plt.ylabel('tan(θ)')
    plt.tight_layout()
    plt.show()
    
    print(f"{angle_deg}° = {angle_rad:.4f} 弧度")
    print(f"tan({angle_deg}°) = {tan_value:.4f}")