假设向量 $\vec{w}$ 的坐标是 $(\sqrt{2} ,\sqrt{3})$. 那么 $\p

def solve():
    from math import sqrt, pi
    import matplotlib.pyplot as plt
    import numpy as np
    
    w = (sqrt(2), sqrt(3))
    w_scaled = (pi * sqrt(2), pi * sqrt(3))
    
    plt.figure(figsize=(8, 6))
    plt.quiver(0, 0, w[0], w[1], angles='xy', scale_units='xy', scale=1, color='blue', label=f'w = ({w[0]:.2f}, {w[1]:.2f})')
    plt.quiver(0, 0, w_scaled[0], w_scaled[1], angles='xy', scale_units='xy', scale=1, color='red', label=f'π·w = ({w_scaled[0]:.2f}, {w_scaled[1]:.2f})')
    
    plt.xlim(-1, 6)
    plt.ylim(-1, 6)
    plt.axhline(y=0, color='k', linewidth=0.5)
    plt.axvline(x=0, color='k', linewidth=0.5)
    plt.grid(alpha=0.3)
    plt.legend()
    plt.title('向量缩放可视化')
    plt.xlabel('x')
    plt.ylabel('y')
    plt.tight_layout()
    plt.show()
    
    print(f"w = ({w[0]:.4f}, {w[1]:.4f})")
    print(f"π·w = ({w_scaled[0]:.4f}, {w_scaled[1]:.4f})")